Excel VBA Val Function
VAL stands for VALUE in VBA terminology. This function converts the string containing numbers to an actual number. For example, if you supply the text string “1234 Global,” it will return only the numerical part, i.e., 1234.
When we download or get the data from web numbers, usually, they are stored as text values in a spreadsheet. However, conversion of text to numbers is the hardest task if you are unaware of the correct function in Excel. As a regular worksheet function, we have a function called VALUE, which will convert all the strings representing numbers to exact numbers with a simple function in the worksheet. This article will show how VBA can achieve this using the VAL function.
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Syntax
It has only one argument: String.
- String: It is simply a string value. We are trying to get the numerical part out of it.
So, the VAL function converts the supplied string to a numerical value.
For example, if the supplied string is “145 45 666 3,” it will ignore the space characters and return the result as “145456663.”
Examples of VAL Function in Excel VBA
Example #1
Let us try the first example with a simple number, “14 56 47.”
The below code is for you.
Code:
Sub Val_Example1()
Dim k As Variant
k = Val(“14 56 47”) ‘Convert the above as 145647
MsgBox k
End Sub
When you run VBA codeRun VBA CodeVBA code refers to a set of instructions written by the user in the Visual Basic Applications programming language on a Visual Basic Editor (VBE) to perform a specific task.read more using the F5 key or manually, it will return the result as “145647” by ignoring all the space characters, as shown below.
Example #2
In this example, we will see that the result of the string is “+456.”
Sub Val_Example2()
Dim k As Variant
k = Val("+456") ‘Convert the above as 456
MsgBox k
End Sub
You can run this code manually or through the F5 key to return the value as 456 by ignoring +456.
Example #3
Now, let’s try the same number with a negative sign.
Sub Val_Example3()
Dim k As Variant
k = Val("-456") ‘Convert the above as -456
MsgBox k
End Sub
This code will only return the value as -456 because it should show the number with the operator sign.
Example #4
Now, let’s try this string “100 Kg.”
Sub Val_Example4()
Dim k As Variant
k = Val("100 KG")
'Ignores KG and returns only 100
MsgBox k
End Sub
If you run this code manually or using the F5 key, the above code ignores “KG” and returns only “100” in the VBA message boxVBA Message BoxVBA MsgBox function is an output function which displays the generalized message provided by the developer. This statement has no arguments and the personalized messages in this function are written under the double quotes while for the values the variable reference is provided.read more.
Example #5
Now, try the date string, “14-05-2018.”
Sub Val_Example5()
Dim k As Variant
k = Val(“14-05-2019”) ‘Returns 14 as the result.
MsgBox k
End Sub
The above code returns 14 because the VAL function can only fetch the numerical value until it finds any other than the numerical character.
Example #6
Now, try the string “7459Good456.”
Sub Val_Example6()
Dim k As Variant
k = Val("7459 Good 456")
'Returns 7459 as the result.
MsgBox k
End Sub
It will extract the numbers until it finds the non-numeric character, i.e., the result is 7459. Then, even though there are numerical values after the non-numerical value “Good,” it completely ignores numbers.
Example #7
Now, try the string value “H 12456.”
Sub Val_Example7()
Dim k As Variant
k = Val("H 12456")
'Returns 0 as the result.
MsgBox k
End Sub
Run the above code using shortcut key F5 or manually, then it returns the result as zero. Because the first character of the string we supplied is non-numerical, the result is zero.
Example #8
Now try this string “24545 . 2”.
Sub Val_Example8()
Dim k As Variant
k = Val("24545 . 2")
'Returns 24545.2 as the result.
MsgBox k
End Sub
The code returns the result as 24545.2 because the VBA VAL function considers the character dot (.) as the decimal character and returns the result accordingly.
Recommended Articles
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